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7. ssm mmh The drawing shows a plane diving toward the ground and then
climbing back upward. During each of these motions, the lift force |
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Since Lift is perpendicular to
displacement, the work done by lift is zero both dive and climb.� The thrust is parallel to displacement, so
the work done by thrust is the same both dive and climb.� The work done by weight however, has a
component in the direction of the displacement in the dive and the component
is in the opposite direction of the displacement in the climb.� So the work for
the dive is positive and the work for the climb is negative for the work done
by weight.� Therefore
the net work is greater for the dive than the climb! |
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The difference in the net work is therefore the difference in the work done by
the weight between the dive and the climb. |
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