PH 201 Post-Lab 06

Friction

Name

Solution

 

Consider the situation shown above.  The coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.45.

 

1. The two blocks are at rest.  Assume the block mass is 0.250 kg, and the hanging mass is 0.075 kg.  What is the static friction force acting on the block mass?

 

Not asked for but a wise student would draw free body diagrams and write out the sum of the force equations which produces:

 

 

 

 

 

 

 

If the masses are not moving, a = 0.  So the static friction force fs is found from

 

We get T from the Hanging mass equation

Substituting that in

 

 

OVER à

 

2. What is the maximum possible static friction force that could act on the block before it starts to move?

 

Maximum possible static friction force is found from

 

From the sum of the force equations

Plugging that into max static friction equation

 

 

 

3. How much mass would the hanging mass have to achieve this maximum static friction force?

Solving for hanging mass

 

 

4. If the masses were moving, assuming the mass of the block is still as 0.250 kg what is the magnitude of the kinetic friction force acting on the block?

 

 

 

 

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This page last updated on January 11, 2020