*21.  mmh The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q1 = +8.00 µC; the other two charges have identical magnitudes, but opposite signs: q2 = -5.00 µC and q3 = +5.00 µC. (a) Determine the net force (magnitude and direction) exerted on q1 by the other two charges. (b) If q1 had a mass of 1.50 g and it were free to move, what would be its acceleration?

w0903

 

 

 

The direction is above  because the signs are opposite so the force is attractive.

 

 

 

 

The direction is above  because the signs are same so the force is repulsive.

 

 

 

So the two force vectors are the same magnitude and look like this

So we find the x and y components and then add or subtract them.  Since the magnitude of  and  is both 0.2128 N, and the x vectors point opposite, the net x component will be zero.  Moreover since both the y components point towards  , the final value will be twice this.

 

 

 

 

 

 

 

Solve for acceleration

 

 

 

 

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This page last updated on June 2, 2018