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*10. A
moving particle encounters an external electric field that decreases its
kinetic energy from 9520 eV to 7060 eV as the particle moves from position A
to position B. The electric potential at A
is -55.0 V, and the electric potential at B
is +27.0 V. Determine the charge of the particle. Include the
algebraic sign (+ or -) with your answer. |
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From Conservation of Energy we
have |
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Solve for q |
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Mathematically we can see this
is a positive charge. Moreover, since
Kinetic Energy decreased as the particle went from negative voltage to a more
positive voltage implies energy is needed to go to a more positive voltage which is what a positive charge would do. |
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