*28. Review Conceptual Example 2 as background for this problem. A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity selector is 3.80 x 103 N/C, while the magnetic field is 0.360 T. When the electric field is turned off, the charged particle travels on a circular path whose radius is 4.30 cm. Find the charge-to-mass ratio of the particle.

 

For a velocity selector we find the sum of the electric force and the magnetic force add to zero.  This provides the relationship

 

 

 

 

Now for the circular path part, use sum of forces in radial direction

 

Solve for speed

 

Use v from velocity selector

Solve for q/m

 

 

 

 

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This page last updated on June 21, 2018