|
|||||||||||||||||||
*38. The drawing shows a bar magnet falling through a metal
ring. In part a the ring is solid all the way around, but in part b it has been cut through. (a) Explain why the motion of the magnet in
part a is retarded when the magnet is above the ring and below
the ring as well. Draw any induced currents that appear in the ring. (b) Explain why the motion of the magnet is
unaffected by the ring in part b. |
|||||||||||||||||||
|
|||||||||||||||||||
|
|||||||||||||||||||
|
|||||||||||||||||||
In the ring in (a) when the
magnet is above the ring, the magnetic field strength is increasing and
pointing down as the magnet falls towards the ring. The increase in magnetic field strength
means an increase in magnetic flux down, so the induced current will go
counter-clock wise and produce a magnetic field going up. This makes the ring producing a “North”
pole above the ring and “Like Poles, Repel” will cause the retardation. |
|||||||||||||||||||
|
|||||||||||||||||||
When the magnet is below the
ring in (a), the field is getting weaker and still pointing down when it
falls so the decreasing field strength means a decreasing magnetic flux, so
the induced current will now want to create a field in the same direction, so
pointing down. The induced current
will go clockwise. Now below the ring
you have a “North” pole and this time it is interacting with the south pole
of the magnet, so you have “Opposite Poles, Attract” going on and that continues
to retard the motion. |
|||||||||||||||||||
|
|||||||||||||||||||
For (b) the ring is not
continuous, so you cannot set up a current and thus you cannot have an
induced magnetic field. So the magnet falls without any slowing due to retarding
forces acting. |
|||||||||||||||||||
|
|||||||||||||||||||
|
|||||||||||||||||||
|
|||||||||||||||||||
|