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76. A woman can read the large print in a newspaper only when
it is at a distance of 65 cm or more from her eyes. (a) Is she nearsighted (myopic) or farsighted
(hyperopic), and what kind of lens is used in her glasses to correct her
eyesight? (b) What should be
the refractive power (in diopters) of her glasses (worn 2.0 cm from the
eyes), so she can read the newspaper at a distance of 25 cm from her eyes? |
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Since the woman cannot read
things close to her she is Farsighted or Hyperopic! So she will need converging lenses. |
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Refractive power is found from
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If focal length is in meters,
Power will be diopters. |
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So we find the focal length. Object distance will be 25 cm – 2 cm = 23
cm. Image distance will be – (65 cm -2
cm = 63 cm) as it needs to be a virtual image. |
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So power is |
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