P 2.5-2 A current source and a voltage source are connected in series with a resistor as shown in Figure P 2.5-2. All of the elements connected in series have the same current, i_s, in this circuit. Suppose that v_s = 10 V, i_s = 3 A, and R = 5 Ω. (a) Calculate the voltage v across the resistor and the power absorbed by the resistor. (b) Change the voltage source voltage to v_s = 5 V and recalculate the voltage, v, across the resistor and the power absorbed by the resistor.

Figure P 2.5-2

(a) Calculate the voltage v across the resistor and the power absorbed by the resistor.

From Ohm’s Law

Power can be found from

(b) Change the voltage source voltage to v_s = 5 V and recalculate the voltage, v, across the resistor and the power absorbed by the resistor.

Again the solutions for v and P do not depend on v_s, they depend on i_s which does not change. So

For both values of voltage of voltage supply, the resistor finds

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