P 3.6-10 Determine the values of i_a, i_b, and v_c in Figure P 3.6-10.

Figure P 3.6-10

We find i_a by first finding R_tot. 10Ω is in series with 20 Ω which is 30 Ω. This 30 Ω is in parallel with the 15 Ω

So 60 V source is in series with 10 Ω Note from polarity defined for 60 V and the drawn direction of i_a, we must have a negative value

Now i_b can be found by current division. Since the resistances split by 15 Ω vs 30 Ω, 2/3 of current will go through 15 Ω resistor.

Note current is going in direction i_b was drawn!

This means 2 A goes through the 20 Ω resistor, but since the current is going to the left, the voltage as drawn implies a negative value.

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This page last updated on January 20, 2019