P 5.5-4 Find the Norton equivalent circuit for the circuit shown in Figure P 5.5-4.

Figure P 5.5-4

Begin by doing a source transformation of the 4 A source and the 8 Ω resistor and the circuit now looks like

Now we can join the 8 Ω and the 3 Ω resistors and do a source transformation with the 32 V source and our circuit becomes

Combining the sources result in a which can transform with the 11 Ω resistor and produce the circuit

Combine the two resistors and do a final transformation and you have a Norton Equivalent circuit

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This page last updated on March 8, 2019