DP 8-1 Design the circuit in Figure DP 8.1 so that v(t) makes the transition from v(t) = 6 V to v(t) = 10 V in 10 ms after the switch is closed. Assume that the circuit is at steady state before the switch is closed. Also assume that the transition will be complete after 5 time constants.

 

DP8_1

Figure DP 8.1

 

For time before t = 0 assuming circuit is in steady state we have

The voltage across the capacitor is equal to voltage across R3 since they are in parallel.  We can determine that by simple voltage division

 

 

So one condition we have is

 

 

So

 

At a later time the circuit is

Again we can use current division and find our next condtion.

 

 

And

 

Plug this back into first equation and we get

 

or

 

Using time constant condition

 

Deactivating power supply to find Thevenin resistance we have

So we have R1 and R3 in parallel

 

 

Using relation

 

Solve for C

So our circuit will work as required changing from 6 V to 10 V in 10 ms if the following equations hold:

There are clearly many Possible answers choose a particular value of R1 and then calculate the rest.  So one answer can be found by choosing R1 to be 1 k

 

 

 

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This page last updated on July 26, 2019